Knapsack problem is also called as rucksack problem. In Knapsack problem, given a set items with values and weights and a limited weight bag . We have to find the optimum solution so that, in minimum cost(value) fill the bag with the maximum weight.
C Program
#include<stdio.h> #include<conio.h> int w[10],p[10],v[10][10],n,i,j,cap,x[10]= {0}; int max(int i,int j) { return ((i>j)?i:j); } int knap(int i,int j) { int value; if(v[i][j]<0) { if(j<w[i]) value=knap(i-1,j); else value=max(knap(i-1,j),p[i]+knap(i-1,j-w[i])); v[i][j]=value; } return(v[i][j]); } void main() { int profit,count=0; clrscr(); printf("\nEnter the number of elements\n"); scanf("%d",&n); printf("Enter the profit and weights of the elements\n"); for (i=1;i<=n;i++) { printf("For item no %d\n",i); scanf("%d%d",&p[i],&w[i]); } printf("\nEnter the capacity \n"); scanf("%d",&cap); for (i=0;i<=n;i++) for (j=0;j<=cap;j++) if((i==0)||(j==0)) v[i][j]=0; else v[i][j]=-1; profit=knap(n,cap); i=n; j=cap; while(j!=0&&i!=0) { if(v[i][j]!=v[i-1][j]) { x[i]=1; j=j-w[i]; i--; } else i--; } printf("Items included are\n"); printf("Sl.no\tweight\tprofit\n"); for (i=1;i<=n;i++) if(x[i]) printf("%d\t%d\t%d\n",++count,w[i],p[i]); printf("Total profit = %d\n",profit); getch(); }