Write a c program or code to find out the sum of series 1^3 + 2^3 + …. + n^3 that is sum of cube of n natural numbers.
Mathematical Formula:
Sum of the series 13 + 23 + 33 + … + n3 = (n (n+1)/2)2
C Program
#include<stdio.h> #include<math.h> int main() { int n,i; int sum=0; printf("Enter the n i.e. max values of series: "); scanf("%d",&n); sum = pow(((n * (n + 1) ) / 2),2); printf("Sum of the series : "); for (i =1;i<=n;i++) { if (i != n) printf("%d^3 + ",i); else printf("%d^3 = %d ",i,sum); } return 0; }
Output:
Enter the n i.e. max values of series: 3 Sum of the series: 1^3 + 2^3 + 3^3 = 36