Python Program to Check Leap Year


Levels of difficulty: / perform operation:

Source Code:

# Python program to check if the input year is a leap year or not

year = int(input("Enter a year: "))
if (year % 4) == 0:
   if (year % 100) == 0:
       if (year % 400) == 0:
           print("{0} is a leap year".format(year))
       else:
           print("{0} is not a leap year".format(year))
   else:
       print("{0} is a leap year".format(year))
else:
   print("{0} is not a leap year".format(year))

Output 1:

Enter a year: 2000
2000 is a leap year


Output 2:

Enter a year: 1775
1775 is not a leap year


Explanation

In this program, we ask the user to input a year and check if it is a leap year or not. Leap years are those divisible by 4. Except those that are divisible by 100 but not by 400. Thus 1900 is not a leap year as it is divisible by 100. But 2000 is a leap year because it if divisible by 400 as well.