Java program to transpose matrix

This java program find transpose of a matrix of any order.

This java program

import java.util.Scanner;
class TransposeAMatrix {
	public static void main(String args[]) {
		int m, n, c, d;
		Scanner in = new Scanner(System.in);
		System.out.println("Enter the number of rows and columns of matrix");
		m = in.nextInt();
		n = in.nextInt();
		int matrix[][] = new int[m][n];
		System.out.println("Enter the elements of matrix");
		for ( c = 0 ; c < m ; c++ )
		         for ( d = 0 ; d < n ; d++ )
		            matrix[c][d] = in.nextInt();
		int transpose[][] = new int[n][m];
		for ( c = 0 ; c < m ; c++ ) {
			for ( d = 0 ; d < n ; d++ )               
			            transpose[d][c] = matrix[c][d];
		}
		System.out.println("Transpose of entered matrix:-");
		for ( c = 0 ; c < n ; c++ ) {
			for ( d = 0 ; d < m ; d++ )
			               System.out.print(transpose[c][d]+"\t");
			System.out.print("\n");
		}
	}
}

Output

This code can be used to check if a matrix symmetric or not, just compare the matrix with it’s transpose if they are same then it’s symmetric otherwise non symmetric, also it’s useful for calculating orthogonality of a matrix.